What is the equation of the line that passes through the point (5, 7) and is parallel to the graph of y = –x – 3?

Question

What is the equation of the line that passes through the point (5, 7) and is parallel to the graph of y = ^–x – 3?

Answer 1

through (5,7) with slope =-1

7=-5 + b

b =12

the parallel line is

y=-x +12 in slope intercept form

x+y = 12 in standard form

x+y -12 =0 in general form

or

y-7 = -(x-5) in point slope form