solve the quadratic equation by factoring

Question

-4+20x-25x^2

Answer 1

5+20x -25x^2

=-5(5x^2-4x-1)

= -5(5x+1)(x-1)=0

x=-1/5 or 1

but if you really meant

-4 +20x -25x^2

then there are no integer factors other than -5,5, -1 or 1

but there are two other irrational factors

-5(x^2 -4x + 4) = 4 -20

-5(x-2)^2 =-16

(x-2)^2 = 16/5

x-2 = +/-4/sqr5

x= 2+4/sqr5, 2-4/sqr5

-5(x-2-(4sqr5)/5)(x-2+(4sqr5)/5)