The height of an object tossed upward with an initial velocity of 152 feet per second

Question

The height of an object tossed upward with an initial velocity of 152 feet per second is given by the formula h = −16t² + 152t, where h is the height in feet and t is the time in seconds. Find the time required for the object to return to its point of departure.

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Answer 1

h= -16t^2 +152t

h(t) = 0 = -16t^2+152t when it returns to ground zero

16t^2 -152t = 0

16t(t -9.5) = 0

t= 9.5 seconds to return to where it started