Raymond B. answered 10/11/22
Math, microeconomics or criminal justice
A=P(1+r/n)^nt
where r= interest rate= .06
n= number of compounding periods per year =12 for monthly compounding
t= number of years= 4
P= starting amount, 10 for $10,000
A=ending amount 7.871 for $7,871
10 = P(1+.06/12)^12(4) = P(1.005^48)
P = 10/1.005^48= about 7.87098411
check by finding continuously compounded amount which should be slightly less
A=Pe^rt
A/10 = e^.06(4) = e^.24
ln(A/10) = .24
lnA-ln10 = .24
lnA = .24+ln10 = .24
$7,871 needed rounded off to nearest dollar
$7,870.98 rounded off to nearest cent
check the answer, use continuous compounding formula and see if it's slightly less
A=Pe^rt = 10= Pe^.24
ln(10/P) = .24
lnP = ln10-.24 = 2.0606
P = e^2.0606 = 7.86646
$7,866.46 is slightly less than $7,870.98
$4.52 less