I need help solving this problem.

Question

Convert the following base-ten number to a number in the indicated base.

62 to base 4

Answer 1

62 base 10 to base 4

= 332

3(4)^2 + 3(4)^1 + 2(4)^0 = 3(16)+12+2 = 48+14 = 62

look at the coefficients of the terms with 4 to a power

3, 3, and 2, string them together

62 in base 13 = 4(13) +X =62, 4X = 62 in base 13 where X is a new digit=10 in base 10

62 in base 12 = 5(12) +2 = 62, 52 =62 in base 12

62 in base 11 = 5(11) +7=62, 57 = 62 in base 11

62 in base 10 = 6(10)+2 = 60+2=62 in base 10

62 in base 9 = 6(9)+8 = 54+8=62, 68 is 62 in base 9

62 in base 8 = 7(8)+6 = 62, 76 is 62 in base 8

62 in base 7 = 1(7)^2 + 1(7)+ 6 =62, 116 is 62 in base 7

62 in base 6 = 1(6)^2 + 4(6) + 2 = 62, 142 is 62 in base 6

62 in base 5 = 2(5)^2 + 2(5) + 2 = 62, 222 is 62 in base 5

62 in base 4 = 3(4)^2 +3(4) + 2 = 62, 332 is 62 in base 4

62 in base 3 = 2(3)^3 + 0(3)^2+ 2(3) +2 = 62, 2022 is 62 in base 3

62 in binary = 1(2)^5 + 1(2)^4 + 1(2)^3+ 1(2)^2 + 1(2)^1 + 0(2)^0 = 32 +16+ 8+4 +2 =62,

111110 = 62 in base 2, 5 ones and one zero

62 in base 1 = 11111111111111111....111111....1111111111111111 (with 62 ones)

from base 2 to base 9, 62 is equal to 11111, 2022, 332, 222, 142, 116, 76, and 68