The slope of the normal (perpendicular) is -1/2.
The point slope form is -1/2 = (y+8)/(x-3).
You should be able to get the other form yourself.
Titus S.
asked 10/07/22Use the given conditions to write an equation for the line in point-slope form and in slope-intercept form. Passing through (3,-8) and perpendicular to the line whose equation is x + 2y = 7
The slope of the normal (perpendicular) is -1/2.
The point slope form is -1/2 = (y+8)/(x-3).
You should be able to get the other form yourself.
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