please help me with this

Question

A combined total of $41,000 is invested in two bonds that pay 6% and 9.5% simple interest. The annual interest is $3,300.00. How much is invested in each bond?

Answer 1

.095x + .06(41,000-x) = 3300

.095x -.06x = 3300 -.06(41000)

.035x = 3300- 2460= 0840

x = 840/.035 = $24,000 invested in 9.5%

41,000-24,000= $17,000 invested in 6%.

average rate of return on the investment is 3300/41000= about 8.0488%

9.5-8.0488= 1.4512

8.0488-6=2.0488

1.4512/2.0488= 7.083

17000/24000= 7.083