Algebra question

Question

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $45. For one performance, 25 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $1200. What was the price of each kind of ticket?

Answer 1

The same type of question keeps popping up. Did you check the Ask An Expert archives for similar ones?

A = Price of advance tiks

S = Price of same-day tiks

A + S = $45 S = $45 - A

25A + 30S = 1200

25A + 30(45 - A) = 1200

25A + 1350 - 30A = 1200

150 = 5A A = $30, so S = $15

Check 25($30) + 30($15) = $750 + $450 = $1200 (Aren't advance tickets usually cheaper, to discourage last-minute sales?)