Given the 2 × 1 matrices,
⌈2 - 9x⌉ ⌈3x - 2⌉
B = | | and C = | |
⌊1 - 4x⌋ ⌊3x - 3⌋
We can find the matrix T that transforms C to B by setting up the following equation.
T · C = B eq. 1
Because C is 2 × 1 and the right hand side of the equation is the 2 × 1 matrix B, we conclude that the transformation matrix T needs to be 2 × 2. Thus,
⌈ a b ⌉
T = | |
⌊ c d ⌋
We can therefore rewrite eq. 1 as the following.
⌈ a b ⌉ ⌈3x - 2⌉ ⌈2 - 9x⌉
| | · | | = | |
⌊ c d ⌋ ⌊3x - 3⌋ ⌊1 - 4x⌋
By performing the matrix multiplication, we get
3ax - 2a + 3bx - 3b = 2 - 9x
3cx - 2c + 3dx - 3d = 1 - 4x
By simplifying, we get
(3a + 3b)x - (2a + 3b) = -9x + 2
(3c + 3d)x - (2c + 3d) = -4x + 1
By setting the coefficients of x equal in each equation, and by setting the constants equal in each equation, we get
3a + 3b = -9
2a + 3b = -2
and
3c + 3d = -4
2c + 3d = -1
By solving the first system, we get
a = -7, b = 4
And by solving the second system, we get
c = -3, d = 5/3
So the transformation matrix T is
⌈ -7 4 ⌉
T = | |
⌊ -3 5/3 ⌋