Find the equation of a line that passes through (8,3) and (-8,-5)

Answer 1

(8,3), (-8,-5)

slope = difference in y values divided by difference in x values= "rise over run" = change in y coordinates divided by change in corresponding x coordinates

(3- -5)/(8- -8) = (3+5)/(8+8)= 8/16=1/2

1/2 = (y-3)/(x-8)

y= (1/2)x -1 is the line's equation in slope intercept form, slope =1/2, intercept = -1

y-3 = (1/2)(x-8) in point slope form

y+5 = (1/2)(x+8) in point slope form using the 2nd point

x-2y =2 in standard from

x-2y-2 =0 in general form

check the answer

plug in the points (8,3) and (-8,-5)

x=8, y=3

3=8/2-1=4-1=3

x=-8, y=-5

-5=-8/2-1=-4-1=-5

x-2y = 2