What is an equation of the line that passes through the point (-6,-8)(−6,−8) and is parallel to the line x-2y=6x−2y=6?

Answer 1

x-2y=6 has slope = 1/2, any parallel line has the same slope

for the point (-6,-8) and generalized point (x,y)

1/2= (y- -8)/(x- -6)

1/2 = (y+8)/(x+6) = difference in y coordinates divided by difference in x coordinates

2y+16 = x+6

x-2y = 10 is the parallel line through (-6,-8), in standard form