If a car has an acceleration of 5.7148 m/s^2, how long will it take to go from 6.94 m/s to 39.8 m/s?

Answer 1

Use kinematics equation V(t)=V(0) +at , and then t=(V(t) -V(0)]/a= [(39.8 m/s -6.94 m/s)]/(5.7148 m/s²)=5.75 s

Answer 2

Acceleration is a rate of change of velocity with units that can sometimes be confusing - m/s² or (m/s)/s. First, subtract the initial velocity, 6.94 m/s, from the final velocity, 39.8 m/s: (39.8 - 6.94)m/s = 32.86 = 32.9 m/s rounded to the appropriate decimal place. This is the change in velocity.

Now, if you divide this change in velocity by the acceleration, you will get the number of seconds it takes for this positive acceleration: 32.9 m/s ÷ 5.7148 m/s² = 5.76 s rounded to the appropriate number of significant figures.