Inactive Tutor answered 10/04/22
The are 21 integers divisible by both 2 and 5.
They are 300, 310, 320, . . . . . , 480, 490, 500.
These are the integers which are divisible by 10 -- which is divisible by 2 and by 5.
Mel V.
asked 10/04/221.) 12
2.) 20
3.) 21
4.) 100
Inactive Tutor answered 10/04/22
The are 21 integers divisible by both 2 and 5.
They are 300, 310, 320, . . . . . , 480, 490, 500.
These are the integers which are divisible by 10 -- which is divisible by 2 and by 5.
Inactive Tutor answered 10/27/25
about 200 integers in that range
to be divisible by 2 and 5 means be divisible by 10 (2x5)
200/10 = 20
answer has to be either 20 or 21
turns out it's 21
because we are sort of getting the end points, 300 and 500, so add 1 to 20 = 21
integers divisible by 5 end in 0 or 5
integers divisible by 2 must be even
So, 300, 310, 320, 330, ..., 500
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