For the first answer I get
26*25 permutations for letters and
10!/3! permutations for numbers
Multiply: 393,120,000
Patricio G.
asked 10/01/22The serial number on a bill consists of a letter followed by seven digits and then a letter. How many different serial numbers are possible, given the letters and digits cannot be repeated?
For the first answer I get
26*25 permutations for letters and
10!/3! permutations for numbers
Multiply: 393,120,000
Raymond B. answered 10/01/22
Math, microeconomics or criminal justice
without repetition would exclude
plates such as C1234567C
or A1233567Z
26P(26-2) x 10P(10-7)
= 26P24 x 10P3
= 26!/24! x 10!/3!
=26x25 x 10x9x8x7x6x5x4
= 650 x 604,800
= 393,120,000
with repetition would
= (26^2)(10^7)
= 276 x 10^7
= 2.76 x 10^9
= 2.76 billion
= 2 billion 760 million
= 2,760,000,000
It's unclear why they would want to exclude repetition as it doesn't mean the license plates or serial numbers repeat, just that a digit repeats. C1234566B and C1234656B have a digit repeat, but the serial numbers are different.
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Doug C.
Since A1234567Z is a different plate than A7654321Z (for example), should be using permutations instead of combinations?10/01/22