Find how old are Juan, Pedro and Miguel

Question

Find three consecutive integers such that the sum of half the smallest and three time the second the second is 16 less than four time the third.

 

Find how old are Juan, Pedro and Miguel

Answer 1

F/2 + 3S = 4T-16

T=S+1

S=F+1

T=F+2

F/2 +3(F+1) = 4(F+2) -16

F/2 +3F +3 = 4F +8 -16

F/2 = 3+16-8 = 11

F = 22

S= 23

T =24

22/2 +3(23) = 4(24)-16

11+69 = 96-16

80 = 80

Smallest = 22 years old = Juan's age

Second = 23 years old = Pedro's age

Third = 24 years old = Miguel's age