Yefim S. answered 02/12/25
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2x + 4yy' - 2 - 8y' = 0; y' = (1 - x)/(2y - 4). At P(0, 3) y' = 1/2.
Tangent line: y = 3 + 1/2x
Yefim S. answered 02/12/25
Math Tutor with Experience
2x + 4yy' - 2 - 8y' = 0; y' = (1 - x)/(2y - 4). At P(0, 3) y' = 1/2.
Tangent line: y = 3 + 1/2x
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