Coin Word Problem Algebra

Question

Jack has 35 coins. He has three less than twice as many dimes than pennies and two more nickels than pennies. How much money does he have?

Answer 1

N=P+2

D=2P-3

N+D+P=P+2+2P-3+P=35

Collect terms to get 4P=36.

You take it from here.

Answer 2

First look for what you need to find.

In this question, you need to find out how much money does Jack have in all?

Look for the information given.

He has a total number of 35 coins, which includes pennies, nickels, and dimes.

Let's name it P, N, and D

P + N + D = 35 _________________ Equation1

3 less than twice as many dimes than pennies can be expressed as,

D = 2P -3______________________Equation 2

2 more nickels than pennies can be expressed as

N = P+2_______________________ Equation 3

When we substitute the values of D and N in equation1, we get,

P+P+2+2P-3 =35

Solve for P

4P = 36

P= 9

D= 2x9 -3 = 15

N= 9 + 2 =11

Total amount = 9P + 15D + 11N = 9x1 + 15x10 + 11x5 = 214 cents.