Hi! So the basic idea of this problem is simple: Two objects collide if all three components of their position vectors are the same at any point in time.
In other words, this means they collide if their x, y, and z coordinates are the same at some time.
So we want:
t2 from r1(t) to equal 4t-3 from r2(t),
7t-12 from r1(t) to equal t2 from r2(t), and
t2 from r1(t) to equal 5t-6 from r2(t)
In math equations, we must solve:
t2 = 4t - 3,
7t-12 = t2,
t2 = 5t-6
You can factor or use the quadratic formula to solve all three of these. You should find that all three have a similar answer of t = 3. This means that at t = 3 all three equalities are true, so the objects will collide.
To find the point of intersection, plug in t= 3 into either r1 or r2 and you'll find their positions.