a(x + b) + cx = d

Answer 1

I assume the question is to solve for X. First, follow PEMDAS to reduce both sides. This includes using the distributive law to multiply a(x+b) to get ax +ab. What remains is the equation ax + ab + cx = d. Then move all constants to one side and all variables to the other. Assuming that x is the variable, subtract ab from both sides. This equation is left ax + cx = d - ab. a and c being unknown coefficients of x meaning that they are still multiples of x. Because both ax and cx share a common multiple, we can factor out the common multiple x. When we factor out x we are left with x(a+c) = d - ab. Divide both sides by (a+c) gives us x = (d - ab)÷(a+c).