Matt L. answered 09/22/22
Math Tutor with Mechanical Engineering Background
For both f(x) and g(x), x is the variable. So, when we're looking at g(2n), that means that we're setting x = 2n. If we take g(x) and plug in 2n for x, we get:
g(x) = x2 – 4x
g(2n) = (2n)2 – 4(2n)
g(2n) = 4n2 – 8n
Now, let's take a look at f(2) + 3. In this case, we're setting x = 2 and then adding 3 to the result of f(2). Let's start by solving for f(2):
f(x) = 2x – 4
f(2) = 2(2) – 4
f(2) = 0
Now to solve f(2) + 3, we just need to substitute f(2) into the equation:
f(2) + 3 = 0 + 3
f(2) + 3 = 3