Peter R. answered 09/22/22
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
Easier to use substitution method rather than elimination.
S + L = 40 so L = 40 - S
9.75S + 15L = 468.75
9.75S + 15(40 - S) = 468.75
9.75S + 600 - 15S = 468.75
-5.25S = -131.25
S = 25 hrs; L = 15 hrs.