Velocity/ acceleration question

Question

When trying to find the function for acceleration is it like finding the derivative.

s(t) = 16 + 24t − 16t²

I know v(t) = -32t+24

Is acceleration = v/t?

Answer 1

Yes! So the 2nd derivative of the position function is the acceleration. In other words, the first derivative of the velocity function. In this case:

a(t) = s"(t) = v'(t) = -32

Answer 2

Yes! The derivative of the position function (s(t)) is the velocity function (v(t)), and in the same way, the derivative of the velocity function is the acceleration function, a(t)

So your acceleration would be the derivative of -32t + 24, which I think you have from there

Spoiler: It's negative thirty two