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Question

In triangle​ ABC, the measure of angle B is

31°

more than three times the measure of angle A. The measure of angle C is

59°

more than the measure of angle A. Find the measure of each angle.

Answer 1

A= measure of angle A

B=3A+31 (31 more than 3 times A)

C=A+59 (59 more than A)

A + 3A + 31 + A+59 = 180 (the sum of the measures of a triangle is 180)

Solve for A, then find B and C using equations above.