Raymond B. answered 09/19/22
Math, microeconomics or criminal justice
about 5.6 seconds to hit the ground
s(t) = 500-16t^2=0
t^2 = 500/16
t = 10sqr5/4 = about 10(2.23)/4 = about 5.6 seconds
v(10sqr5/4)
= -32(10sqr5/4)
= -80sqr5
= about -80(2.23)
= about -179 ft/sec
it decelerates due to gravity at 32 ft/sec/sec for about 5.6 seconds
-32(5.6) = about -179 ft/sec