Raymond B. answered 09/18/22
Math, microeconomics or criminal justice
f(x) = (sqr(x+5))/(x+5)(x-3)
or
f(x) = sqr(x+5)/(x^2 +2x -15)
or
f(x) =1/(x-3)(sqr(x+5))
have domain = (-5,3)U(3,infinity)
3 or -5 are not possible values for x, as they make the denominator =0. division by zero is not defined
x<-5 is not possible as it makes the square root of x+5 imaginary
that leaves the domain as -5<x<3 and 3<x<infinity