Calculus Question

Question

If x(t)=−2t^2+6t+3x(t).

find the position of the object at t=3.7s.t=3.7s. Use standard SI units.

Find the velocity of the object at t=3.7s

Find the velocity of the object at t=3.7s

Answer 1

x(t) = -2t^2 +6t + 3

x(3.7) = -2(3.7)^2 +6(3.7) + 3

=-27.38 + 22.2 + 3

= -2.18 meters

v(t) = x'(t) = -4t +6

v(3.7) = -4(3.7)+6= -14.8+6 = -8.8 meters per second