Problem on Probability

Question

Three boys A, B, and C play a game in which the loser is to double the marbles of each of the other

two. After three games, each has lost exactly once and each ended up with 48 marbles. How many

marbles did each have initially?

Answer 1

A originally had 42 marbles

B originally had 78 marbles

C originally had 24 marbles

B loses and the marbles are A=84, B=12, C=48

A loses and the marbles are A =24, B=24 C=96

C loses and the marbles are 48 each

total marbles are 3(48) = 144