how much money was invested into each account?

Question

A total of $3300 is invested in two accounts. Account A pays 3% interest per year, and Account B pays 6% interest per year. If the total interest earned is $153.

Answer 1

.06x + .03(3300-x) = 132

.06x-.03x = 132 -.03(3300)

.03x = 132 -99 =33

x = 33/.03 = $11,000 invested at Account B's 6%

3300-x = $22,000 invested at Account A's 3%

132/3300 = .04 = 4%

6-4=2

4-3 =1

2/1 =2

twice as much 3% is needed as 6%

$2200 invested at 3%

$1100 invested at 6%

2200 is twice 1100