The perimeter of a college athletic field is 100 meters and the length is 16 m more than the width. Find the length and width

Question

The perimeter of a college athletic field is 100 meters and the length is 16 m more than the width. Find the length and width

Answer 1

Assign variables:

Let the width = x. Since the length is 16 more than the width, the length = x +16

Set up the perimeter equation:

The perimeter of a rectangle is P = 2 (length) + 2 (width)

Substituting, we get:

2x + 2(x+16) = 100

Simplify:

2x + 2x + 32 = 100 ⇒ 4x + 32 = 100

Solve for x:

Subtract 32 from both sides:

4x = 68

Divide both sides by 4:

x = 17

So the width = 17 m and the length = 17 + 16 = 33 m.

Final Answer: Width = 17 m, Length = 33 m.

Answer 2

P=100 = 2L+2w

L+w = 50

L = 16+w

16+w + w = 50

2w = 50-16 = 34

w = 34/2 = 17 meters wide

L = 50-17 = 33 meters long

Answer 3

P=100 = 2L+2w

L+w = 50

L = 16+w

16+w + w = 50

2w = 50-16 = 34

w = 34/2 = 17 meters wide

L = 50-17 = 33 meters long

Answer 4

w + w + 16 = 50

2w + 16 = 50

Can you solve for w and answer?

Answer 5

First, we need to assign variables for our unknown values. We will let x = width and since we were told that the length is 16 more than the width, we will use x + 16 = length.

Therefore, we have

x = width

x + 16 = length

For perimeter, you add up all the sides. For a rectangle, you will have two width measurements and two length measurements.

You will set up your equation x + x + x + 16 + x + 16 = 100. They told us that the perimeter is 100.

Combine like terms and add all the x's to get 4x. Add the number and get 32.

4x + 32 = 100

Then you will solve the two-step equation. They are adding 32 so we will subtract 32 from both sides. That will leave us with

4x = 68

Then divide both sides by 4

That will leave us with x = 17

Therefore the width = 17

The length is x + 16 = 17 + 16 = 33

width = 17

length = 33