How do I write a slope intercept equation for a line that passes through a point and is parallel to a vertical line?

Question

How would I write the slope-intercept equation of a line that passes through(6,-6) and is parallel to x=-1?

How would I write a second equation for a line that passes through (6,-6) but is perpendicular to x=-1?

Answer 1

The graph of x=-1 is a vertical line. The lines parallel to this would also be a vertical line. The vertical line that goes through the point (6,-6) is x=6

The line perpendicular to this would be a horizontal line, that is in the form y=constant. The line that goes through the point (6,-6) is y=-6

Answer 2

All vertical lines are parallel as are all horizontal lines.

A line parallel to x = -1 is also vertical. The vertical line that passes through the point (6, -6), is x = 6. Every point on that vertical line will have an x-coordinate of 6.

Lines that are perpendicular to x = -1 will be horizontal (any vertical line forms a right angle with any horizontal line.

The equation of a line perpendicular to x = -1 and passing through (6, -6) will be y = -6. Every point on that horizontal line will have a y coordinate of -6.

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