Find a number that is 68 greater than its opposite

Answer 1

x = 68 + 1/x, if by "opposite" the problem means inverse, then

x^2 = 68x + 1

x^2 -68x -1 = 0

x = 68/2 +/- (1/2)sqr(68^2 +4) = 34 +/-.136.015 = 170.015 or - 102.015

BUT "opposite" might more likely mean negative as in opposite sign. Then

x= 68+ (-x) = 68-x

2x = 68

x = 34