Train A has a speed 20 miles per hour greater than that of train B. If train A travels 160 miles in the same times train B travels 120 miles, what are the speeds of the two trains?

Answer 1

A = 20 + B = speed of Train A

Train A goes 160 miles in same time that Train B goes 120 miles

distance = speed times time

d=rt

160 = At

t = 160/A = 160/(20+B) = 120/B

multiply by (20+B)B

160B = 120(20+B)

divide by 40

4B = 3(20+B)

4B = 60+3B

B = 60 mph

A = 80 mph

in 2 hours A goes 2(80) = 160 miles

in 2 hours B goes 2(60) = 120 miles