Raymond B. answered 09/03/22
Math, microeconomics or criminal justice
3R, 5W, 7Y
a) P(R) = 3/(3+5+7) = 3/15 = 1/5 = 20% propability of red
b) P(W) = 5/(15) = 1/3 = 33 1/3% probability of white
c) P(Y) = 7/15 = 0.4666... = 46 2/3% probability of yellow
20+33 1/3 + 46 2/3 = 100%
that assumes the random drawings are with replacement, or just independent events
without replacement, in order Red, White, then Yellow
a) P(R) = 1/5 = 20% chance of Red on 1st draw
b) P(W) = 5/14 = 0.3571428571428571428... = about 35.7% chance of White on 2nd draw
c) P(Y) = 7/13 = 53.8% chance of Yellow on 3rd draw
these 3 probabilities do not sum to 100%