Find perpendicular line that passes through (-4,-3) and (2,-9)

Answer 1

(-4,-3) and (2,-9) have a straight line through them: (-3- -9)/(-4 -2) = (6/-6)= -1 = (y+3)/(x+4)

slope =-1. for a line perpendicular, the slope is the negative inverse = +1

y =x +b where b is the y intercept.

Perpendicular through (-4,-3):

-3 =-4 +b

b =1

y = x+1 is the perpendicular line through one end point of the given line segment

Pependicular through (2,-9)

-9 =2+b

b=-11

y= x-11 is the perpendicular line through the other end point