Raymond B. answered 09/01/22
Math, microeconomics or criminal justice
x +4y = 28 endpoints (0,7) and (28,0)
2x +8y =56
2x +y = 28 endpoints (0,28), (14,0)
subtract
7y = 28
y=28/7 = 4
x = 28-4(4) = 12
(12,4) is a potential point of minimum cost
c=x+2y= 12+2(4) = 20
try the other end points, vertexes of the boundary lines
c(0) = 2(28) =56
c(28) = 28+0= 28
(12,4) is the cost minimizing point with c= 20