Raymond B. answered 09/01/22
Math, microeconomics or criminal justice
.8x +.8y > 8
multiply by 10/8
x + y > 10
it's endpoints are (0,10) and (10,0)
x+2y > 14
this constraint is bounded below by a line from endpoint (0,7) to endpoint (14,0)
the two bounday lines intersect at a point which is possibly a cost minimizing point
the 2nd constraint line boundary is the same as C=2x+4y =28
divide by 2 to get x+2y =14,
x+y=10 and x+2y= 14 intersect
subtract 1st equation from 2nd to get
2y-y = 14-10
y=4, and x=6, the intersection point is (6,4)
c(x) = c(6)= 2x+4y = 2(6)+4(4) =12 +16= 28
endpoints
have c(14)=2(14)+0= 28
cost is minimized at any point on the line segment from (6,4) to (14,0)
an infinite number of points including (6,4), (8,3), (10,2), (12,1), (14,0)
all have cost = 28= minimum cost
Aaa A.
what is the occurs at the endpoints (x, y) = ? (smaller x-value) and what is the endpoints (x, y) = ? (larger x-value)09/01/22