If three times the largest of three consecutive integers is 34 less than 5 times the smallest, then how would you get the answer?

Answer 1

Let x = smallest integer

then: x + 1 = middle integer

and x + 2 = largest integer

3 (x+2) is three times the largest

5x - 34 is 34 less than three times the smallest

Those numbers are equal ("is"):

3(x+2) = 5x - 34

3x + 6 = 5x - 34

40 = 2x

x = 20

The integers are 20, 21, 22

3(22) =? 5(20) - 34

66 =? 100 - 34

66 = 66 √