Raymond B. answered 08/31/22
Math, microeconomics or criminal justice
A=P(1+r/n)^nt
where r=annual interest rate,
n=number of compounding periods per year,
t = number of years
P= amount invested
A = amount after t years at r interest rate compounded n times per year
3500=P(1+0.075/2)^2(4)
P = 3500/(1.0375)^8
P = $2607.13 invested today
7.5% compouned biannually for 4 years yields $3500