college algebra

Question

the length of a new playing field is 5 yards longer than quadruple the width. if the perimeter of the rectangular playing field is 520 yards, what are its dimensions?

Answer 1

L = 5+ 4W

P = 520 = 2(L+W)

= 2(5+4W+W)

= 2(5+5W)

520= 10+10W

10W = 520-10 = 510

W = 510/10 = 51 yards Wide

L = 5+4(51) = 5+204 = 209 yards Long

51+209= 260

2(260) = 520 = Perimeter

dimensions are 51 by 209 yards