Peter R. answered 08/28/22
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
f(1) = 15 (given)
f(2) = f(2 - 1) - 10 = f(1) - 10 = 15 - 10 = 5
f(3) = f(3 - 1) - 10 = f(2) - 10 = 5 - 10 = -5
f(4) = f(4 - 1) - 10 = f(3) - 10 = -5 - 10 = -15
This is equivalent to an arithmetic sequence with 1st term = 15, difference of -10.
an = a1 + (n - 1)d a1 = 15, n = 4, d = -10, an = nth term in the sequence
an = 15 + (4 - 1)(-10) → 15 + (3)(-10) → 15 + (-30) = -15