Randy had grades of 85, 92, 96 and 89 on his last 4 math tests. What grade does he need on bis next test to have an average of 92%

Question

HELP MEEE

Answer 1

Phoenix's answer is perfect. A different way to look at it: to get an average of 92, the differences from 92 must sum to 0, or the difference for the last grade must be the negative of the sum of the other differences.

(85 - 92) + (92 - 92) + (96 - 92) + (89 - 92) = -7 + 0 + 4 + -3 = -6

92 - -6 = 98

Answer 2

With the grade Randy is looking for, it will be an average of 5 total scores being an 85, 92, 96, 89, and an unknown(x). If you look at it like this (85+92+96+89+x)/5=92 you can solve for x. Simplifying the addition, it comes to (362+x)/5=92. Then multiply to cancel the 5, making it come to (362+x)=460 and subtract the 362 to find that x=98, meaning he will need a 98 to bring that average to a 92.