A 48 ft wire is cut into three pieces, the second one is 3 times as long as the first piece. The third piece is four times as long as the second piece. How long is each piece.

Question

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Answer 1

48 =A + B + C

48= A + B + 4B

B= 3A

A= B/3

48= B/3 + B + 4B

48= B/3 +5B

48= (5B/15 )+ (15B/15 )

48=20B

B= 2.4

Combine like terms

48= A + 5B

.express this equation in terms of B again and substitute in for A

Now you have A being expressed in terms of B and C being expressed in terms of B.

Now you can solve for B and plug it into the former equations.

Combine like terms

Now adjust your equation

C= 2.4*4= 9.6

B=2.4

By process of elimination you can now solve for A

48= A+ 2.4 + 9.6

48= A + 12

A = 36

So A would be 36 ft, B would be 2.4ft, and C would be 9.6 ft.

All integers would sum to 48 ft as indicated and required.

Answer 2

f represents the length of the first piece

3f represents the length of the second piece

4(3f) represents the length of the third piece

f + 3f + 4(3f) = 48

Can you solve for f and answer?