Karl M. answered 08/24/22
Experienced, Highly Rated Undergraduate Math and Physics Tutor
Firstly we are bound in that we can only have up to 3000 reserved seats and therefore 3000 reserved tickets:
x ≤ 3000.
If we can have at most 4000 attendees then we can only sell at most 4000 total tickets. Since x represents the number of reserved tickets and y represents the number of general admission tickets, the total amount of tickets to be sold is x + y. Since this has to be less than or equal to 4000:
x + y ≤ 4000.
This gives us two inequalities, but we can write one more. We know the promoter must take in at least $367,500. This means the total revenue of the ticket sales must be greater than or equal to 367500 dollars. If each reserved ticket is sold at $100 and we sell x amount of them, the revenue for the reserved tickets would be 100 times x; similarly for the general admission tickets their revenue would be 90 times y. Thus,
100x + 90y ≥ 367,500.