
Yefim S. answered 08/24/22
Math Tutor with Experience
6t + 2 = 2s + 2; 7 = 2s + 7; - t + 1 = s + 1
6t = 2s; 2s = 0 - t = s;
s = 0, t = 0.
So, (x, y, z) = (2, 7, 1) iz intersection point
Dirction vector of 1st line u = <6, 0, -1>; direction vector of 2nd line: v = <2, 2, 1>
cosθ = (6·2 + 0·2 - 1·1>/(√37·√9) = 11/(3√37); θ = cos-1(11/(3√37) = 52.9°