Raymond B. answered 08/16/22
Math, microeconomics or criminal justice
doubling time in 1 year, at continuously compound growth means
260=130e^r(1)
2= e^r
take natural logs of both sides
ln2 = r
r = ln2 = about .69
A= 130e^.69n or 130e^(nln2)
After 4 hours it doubled 4 times
from 130 to 260,
then to 520 after 2 hours
then to 1040 after 3 hours,
then to 2080 after 4 hours
or
A = 130e^4ln2 = 130(16) = 2080 cells
to determine time in minutes when it reaches a given level of cells,
set A= to the number of cells and solve for m
A= 130e^(m/60)ln2
A/130 = e^(m/60)ln2
take natural logs of both sides
ln(A/130) = (m/60)ln2
m/60 = ln(A/130)/ln2
m= 60ln(A/130)/ln2
or just solve for t and use
A=130e^tln2 where t= hours,
ln(A/130)= tln2
t = ln(A/130)/ln2 = number of hours to reach a given level, A, of cells = log2(A/130)
then multiply by 60 , 60t, to get the number of minutes:
m=60t = numeber of minutes to reach A, = 60t = 60ln(A/130)/ln2 or 60log2(A/130)