The perimeter of a rectangle is 44 in. Find the length and the width if the length is 5 in. Less than twice the width?

Question

The perimeter of a rectangle is 44 in. Find the length and the width if the length is 5 in. Less than twice the width?

Thank you

Answer 1

L= 2W-5

P= 2(L+W) = 2(2W-5+W) = 2(3W-5) = 6W -10 = 44

6W = 44+10 = 54

W = 54/6 = 9 inches Wide

L= 2(9)-5 = 18-5 = 13 inches Long