There's a pool of 11×38 = 418 available unskilled and 6×38 = 228 available skilled work hours per week.

The objective function to maximize is

p = s·100 +c·160 [profit in dollars],

where s = # of study tables and c = # of computer tables produced (and sold) weekly.

The following inequalities determine the feasible region:

(1) 0 ≤ s

(2) 0 ≤ c

(3) s·2 +c·2 ≤ 228 [skilled work hours used]

(4) s·2 +c·5 ≤ 418 [unskilled work hours used]

The optimal strategy is s = 51 & c = 63 with a profit of $15,180.