find three consecutive odd integers such that five times the sum of the first and second is 4 times more than 8 times the third

Question

find three consecutive odd integers such that five times the sum of the first and second is 4 times more than 8 times the third

Answer 1

5(F+S) = 12(T)

F=x-2

S=x

T=x+2

5(x-2+x) = 12(x+2)

10x -10 = 12x +24

2x = -34

x=-17

x= -17 = the Second Number

x-2 =-19 = the First Number

x+2 = -15 = the Third Number

5(F + S) = 12T

-5(-19-17)= 12(-15)

-5(36) = -180

-180 = -180