Using the graph of y=2x^3-x^2+3 attached below, solve the equation 2x^3-7=0.

Question

Using the graph of y=2x^3-x^2+3 attached below, solve the equation 2x^3-7=0. Image: https://drive.google.com/file/d/1qDA9Z4ZRIBXOh_1i2rr_lYClwSIzL1YN/view?usp=sharing

Answer 1

y = 2x^3 -x^2 + 3

2x^3 -7 = 0

x^3 = 7/2

x = cube root of 3.5 = about 1.52

y = 2(7/2) -(1.52)^2 +3 = 10-2.3 = 7.7

solution is about (x,y) = (3.5, 7.7)