Raymond B. answered 08/02/22
Math, microeconomics or criminal justice
x y z
-3 2 13
-3 3 12
-3 4 11
-3 5 10
-3 6 9
-3 7 8
-3 8 7
-3 9 6
-3 10 5
-3 11 4
10 solutions with x =-3
-2 2 12
through
-2 11 3
10 more with x=-2
-1 2 11
through
-1 10 3
9 more with x =-1
0 2 10
through
0 9 3
8 more with x=0
1 2 9
through
1 8 3
7 more with x= 1
2 2 8
through
2 7 3
6 more with x=2
3 2 7
through
3 6 3
5 more with x=3
4 2 6
through
4 5 3
4 more with x = 4
4+5+6+7+8+9+10+10 = 59 integer solutions
when -2<x<4, 2<y<11 amd z>3
and x+y+z=12